| Package | Description |
|---|---|
| dev.nm.analysis.differentialequation.ode.ivp.problem | |
| dev.nm.analysis.differentialequation.ode.ivp.solver |
Numerical solutions of ordinary differential equation initial-value problems.
|
| dev.nm.analysis.differentialequation.ode.ivp.solver.extrapolation | |
| dev.nm.analysis.differentialequation.ode.ivp.solver.multistep.adamsbashforthmoulton | |
| dev.nm.analysis.differentialequation.ode.ivp.solver.rungekutta |
| Class and Description |
|---|
| DerivativeFunction
Defines the derivative function F(x, y) for ODE problems.
|
| ODE
An ordinary differential equation (ODE) is an equation in which there is only one independent
variable and one or more derivatives of a dependent variable with respect to the independent
variable, so that all the derivatives occurring in the equation are ordinary derivatives.
|
| ODE1stOrder
A first order ordinary differential equation (ODE) initial value problem (IVP) takes the
following form.
\[
y' = f(x, y) \\
y(x_0) = y_0
\]
where \(y_{0}\) is known, and the solution of the problem is y(x) for the
integrating interval \([x_{0}, x_{1}]\).
|
| Class and Description |
|---|
| ODE1stOrder
A first order ordinary differential equation (ODE) initial value problem (IVP) takes the
following form.
\[
y' = f(x, y) \\
y(x_0) = y_0
\]
where \(y_{0}\) is known, and the solution of the problem is y(x) for the
integrating interval \([x_{0}, x_{1}]\).
|
| Class and Description |
|---|
| ODE1stOrder
A first order ordinary differential equation (ODE) initial value problem (IVP) takes the
following form.
\[
y' = f(x, y) \\
y(x_0) = y_0
\]
where \(y_{0}\) is known, and the solution of the problem is y(x) for the
integrating interval \([x_{0}, x_{1}]\).
|
| ODE1stOrderWith2ndDerivative
Some ODE solvers require the second derivative for more accurate Taylor series approximation.
|
| Class and Description |
|---|
| DerivativeFunction
Defines the derivative function F(x, y) for ODE problems.
|
| ODE1stOrder
A first order ordinary differential equation (ODE) initial value problem (IVP) takes the
following form.
\[
y' = f(x, y) \\
y(x_0) = y_0
\]
where \(y_{0}\) is known, and the solution of the problem is y(x) for the
integrating interval \([x_{0}, x_{1}]\).
|
| Class and Description |
|---|
| DerivativeFunction
Defines the derivative function F(x, y) for ODE problems.
|
| ODE1stOrder
A first order ordinary differential equation (ODE) initial value problem (IVP) takes the
following form.
\[
y' = f(x, y) \\
y(x_0) = y_0
\]
where \(y_{0}\) is known, and the solution of the problem is y(x) for the
integrating interval \([x_{0}, x_{1}]\).
|
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